Question

If zeros of quadratic polynomial x?(a + 1) x + b are 2 and 3 than. (i) a = - 7, b = -1​

Answer 1

Step-by-step explanation:

29.(i)

\begin{gathered}97 = (100 - 3) \\ = ( {100}^{2} + {3}^{2} - 2 \times 100 \times 3) \\ = 10000 + 9 - 600 \\ = 9409 \\ \end{gathered}

97=(100−3)

=(100

2

+3

2

−2×100×3)

=10000+9−600

=9409

29.(ii)

\begin{gathered}992 = (1000 - 8) \\ = ( {1000}^{2} + {8}^{2} - 2 \times 1000 \times 8) \\ = 1000000 + 64 - 16000 \\ = 984064 \\ \end{gathered}

992=(1000−8)

=(1000

2

+8

2

−2×1000×8)

=1000000+64−16000

=984064

29.(iii)

\begin{gathered}9.98 = (10 - 0.02) \\ = ( {10}^{2} + {0.02}^{2} - 2 \times 10 \times 0.02) \\ = 100 + 0.0004 - 0.4 \\ = 99.6004\end{gathered}

9.98=(10−0.02)

=(10

2

+0.02

2

−2×10×0.02)

=100+0.0004−0.4

=99.6004

$\alpha \beta \gamma \alpha \beta \gamma \alpha \beta \gamma \alpha \gamma \alpha log_{ ln( log_{ \cot(?) }(?) ) }(?)$