Question

if zeros of the polynomial f(x) =
${x}^{3} - 3p {x}^{2} + qx - r$
are in AP , then
$(a)2 {p}^{3} = pq - r \\ (b)2 {p}^{3} = pq + r \\ (c) {p}^{3} = pq - r \\ (d)none \: of \: these$​

Answer 1

$\huge {\purple {\fbox {\bigstar {\mathfrak {\underline {ANSWER}}}}}}$

$\red{option\:(a)2 {p}^{3} = pq - r }$

Explanation is in the above attachment.

$\huge {\pink {\fbox {\fbox {\mathfrak {hope \: it \:helps\: you}}}}}$