Math, asked by abc112004, 3 months ago

If |zI = 1 and z ≠ ± 1, then all the values of z/( 1- z^2) − lie on ​

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Answered by Dhruv14372
1

Answer:

Explanation: Hence, z/1 - z2 lies on the imaginary axis ie,y-axis. Let E = z/(1 - z2) = z/(z bar z - z2) = 1/(z bar - z) which is imaginary.

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