If |zI = 1 and z ≠ ± 1, then all the values of z/( 1- z^2) − lie on
Answers
Answered by
1
Answer:
Explanation: Hence, z/1 - z2 lies on the imaginary axis ie,y-axis. Let E = z/(1 - z2) = z/(z bar z - z2) = 1/(z bar - z) which is imaginary.
Similar questions