Question

If Zi=3+2i and Z2=1-i, find [z1+z2+1/z1-z2+1]^2​

Answer 1

Answer:

z1+z2

=1+i+3-2i

=4-1i

z1-z2

=1+i-(+3-2i)

=1+i-3+2i

=-2+3i

z1×z2

(1+i)×(3-2i)

=3+(-2i)+3i-2i²

=3-2i+3i-2i²

=-2i²+3i+3

z1/z2

=1+i/3-2i

Step-by-step explanation:

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