Question

if0.80 mole of MnO2 and 146g of HCL react then​

Answer 1

Answer:

The balanced reaction is given below:

1molMnO 2 + 4mol4HCl ⟶MnCl 2 + 1molCl 2 +22

O

Initial 0.8 mol 4 mol 0 mol

After 0 mol 4−3.2=0.8 mol 0.8 mol

146gHCl=

36.5

146

=4mol

Thus, MnO 2

(less) is limiting reagent.

HCl (more) is in excess.

Amount of product is decided by MnO 2

.

Therefore, Cl 2

formed=0.8mol and HClunreacted=0.8mol.

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