if0 and 1 are the zeroes of the polynomial S(x) = 2x^3 - 3x^2 + ax + b, find the values
of a and b.
Answers
EXPLANATION.
→ 0 and 1 are the zeroes of the polynomial
s(x) = 2x³ - 3x² + ax + b,
→ To find the value of a and b.
→ Case = 1.
→ put the value of x = 0 in equation
→ s(0) = 2(0)³ - 3(0)² + a(0) + b = 0
→ s(0) = 0 - 0 + 0 + b = 0
→ s(0) = b = 0 ..... (1)
→ Case = 2.
→ put the value of x = 1 in equation
→ s(1) = 2(1)³ - 3(1)² + a(1) + b = 0
→ s(1) = 2 - 3 + a + b = 0
→ s(1) = -1 + a + b = 0
→ s(1) = a + b = 1 .......(2)
→ put the value of equation (1) in (2)
we get,
→ a + 0 = 1
→ a = 1
→ Therefore, value of a = 1 and b = 0.
Step-by-step explanation:
Given : -
- the zeroes of the polynomial S(x) = 2x^3 - 3x^2 + ax + b,
.To Find : -
- find the values of a and b.
Solution : -
f(0) = 0 and f(1) = 0
✪ substitute all values :✪
➻ f(0) = 2(0)³ - 3(0)² + a(0) + b = 0
➻ b = 0.......(1)
f(1) = 2(1)³ - 3(1)² + a(1) + b = 0
✪ Substitute all values :✪
➻ 2 - 3 + a + b = 0
➻ a + b - 1 = 0
➻ a + b = 1 ........(2)
from equations (1) and (2),
a + b = 1
b = 0
________
a = 1
hence, value of a = 1 and b = 0