Math, asked by unnavatushar37, 10 months ago

if1/3is one zero of3x²+5x-3 then find the other zeros

Answers

Answered by brainlyaryan12

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Let $\alpha\:be \:\frac{1}{3}$

$\alpha+\beta=\frac{-b}{a}$

$\frac{1}{3}+\beta=\frac{-5}{3}$

=> $\beta = \frac{-5}{3}-\frac{1}{3}$

=> $\beta = -2$

$\huge\orange{\fbox{\pink{\therefore \beta=-2}}}$

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