Question

if1-i is a root of the equation x2 + ax+b=0 where a,b€R then find the value of a and b​

Answer 1

Step-by-step explanation:

If (1-i) is a root of the quadraric equation x² + ax + b = 0 then the other root is conjugate of (1-i) i.e. (1+i)

So, x² + ax + b = (x - 1 - i) (x - 1 + i) = x² -x + xi -x +1 -i -xi + i - (i²) = x² -2x + 2

∴ a = -2 & b = 2