If2/3=cos find value of 4+4tanA
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Answered by
1
cos = 2/3
Hence, cos = adjacent/hypo = 2/3
Hence, (opposite)^2 = (hypo)^2 - (adjacent)^2
opposite = √(9 - 4)
opposite = √5
Hence sin = √5/3. ( since, sin= opposite/hypo)
4+4tan = 4(1 + tan)
= 4(1 + sin/cos)
= 4[1 + (√5/3)/(2/3)]
= 4 (1 + √5/2)
= 4 [(2+√5)/2]
= 4 [(2+ 2.23)/2] or 2(2+√5)
= 2 (4.23) or 4 + √5
= 8.46 or 4 + √5
There u go....
Hope it helped
Hence, cos = adjacent/hypo = 2/3
Hence, (opposite)^2 = (hypo)^2 - (adjacent)^2
opposite = √(9 - 4)
opposite = √5
Hence sin = √5/3. ( since, sin= opposite/hypo)
4+4tan = 4(1 + tan)
= 4(1 + sin/cos)
= 4[1 + (√5/3)/(2/3)]
= 4 (1 + √5/2)
= 4 [(2+√5)/2]
= 4 [(2+ 2.23)/2] or 2(2+√5)
= 2 (4.23) or 4 + √5
= 8.46 or 4 + √5
There u go....
Hope it helped
Answered by
4
If cos A = 2/3 = Base(B)/Hypotenuse(H)
So we can calculate Perpendicular (P)
Hence
Now we can calculate
tan A = Perpendicular (P)/Base(B)
Now put the value in
4 + 4 tanA
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