Math, asked by bijaykumarraula703, 4 months ago

If2*345 is divisible by 9 what will come at ?
(A) 4
(B) 1
(C) 9
(D) 8

Answers

Answered by lavanyasaxena395
2

Answer:

a option is correct

Step-by-step explanation:

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Answered by aarushi229960
2

Answer:

Hint: a natural number is divisble by 9 if and only if the sum of its (decimal) digits is divisible by 9 .

A full solution: denote the missing digit by d . Then

2d345===2×10,000+d×1,000+3×100+4×10+5(2×(9,999+1)+d×(999+1)+3×(99+1)+4×(9+1)+5(2×9,999+d×999+3×99+4×9)+(2+d+3+4+5)

The expression in the first brackets is divisible by 9 , hence the number 2d345 is divisble by 9 if and only if expression in the second brackets, 2+d+2+4+5 is divisible by 9 . We are almost there:

2+d+3+4+5=d+14,

and we need to take d=4 to make it 4+14=18 .

As you can see, it is all about the so-called ‘place value’ in arithmetical

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