If2 moles of common salt are dissolved in 1 litre of its solution,
then what is the molarity of the solution
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Given, no. of moles of NaCl = 2
Volume of solution = 1 litre
We know, Molarity = no. of moles of solute / vol. of solution in litre
i.e. M = n / V (in L)
M = 2 / 1 = 2 mol/L
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