if2^x-1=1÷8^x-3 find x
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Answer:
2(2x - 1) = \frac{1}{8} (x - 3)2(2x−1)=
8
1
(x−3)
16(2x - 1 )= x - 316(2x−1)=x−3
32x - 16= x - 332x−16=x−3
31x= 1331x=13
x = \frac{13}{31}x=
31
13
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