Question

if3^x+1= 9^x-2,find the value of 2^1+x​

Answer 1

QUESTION :-

• if 3ˣ⁺¹ = 9ˣ⁻² , find the value of 2¹⁺ˣ

SOLUTION :-

→ 3ˣ⁺¹ = 9ˣ⁻²

→ 3ˣ⁺¹ = 3²⁽ˣ⁻²⁾ ( Base are equal so comparing exponent )

→ x + 1 = 2( x -2 ) ( pᵐ = pⁿ ⇒mn )

→ x + 1 = 2x - 4

→ x - 2x = -1 -4

→ -x = -5

→ x = 5

Now :-

• finding the value of 2¹⁺ˣ

→ 2¹⁺ˣ

→ 2 ¹⁺⁵

→ 2⁶

→ 64

Hence :-

• Value of 2¹⁺ˣ is = 64

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Answer 2

Step-by-step explanation:

64 is Ur answer

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