if42× 5 is a multiple of 9 or x is a digit ,then find the value of x
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the sum of the digit of the given number should be devisible by nine if the 9is the multiple of 42x5.so, sure of the digit not including X is 4+2+5= 11 to get the multiple of 9 we should at least get 18 so we replace the X by 7 to get the whole sum of the digit 18
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