Math, asked by SohailShirazi, 6 months ago

If4tanA=3thenFind

4sinA-cosA

4sinA+cosA​

Answers

Answered by namratha9124
2

Answer:

8/5,16/5

Step-by-step explanation:

4tanA=3

TanA =3/4=Opposite side/Adjacent side

Therefore, Opposite side=3

Adjacent side=4

Hypotenuse=5 ( Hyp²=Side²+Side²)

SinA=Opposite side/Hypotenuse=3/5

CosA=Adjacent side/Hypotenuse=4/5

4sinA=12/5

4sinA-CosA=12/5-4/5=8/5

4sinA+cosA=12/5+4/5=16/5

Answered by prasayan2005
0

Answer:

if 4tanA=3

then

4sinA+cosA=(4sinA+cosA)/cosA=4tanA+1=3+1=4

4sinA-cosA=(4sinA-cosA)/cosA=4tanA-1=3-1=2

plz mark my answer as brainlist

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