Question

If4x^2+9y^2=136 and xy=10 find(2x+3y)^2 ?

Answer 1

Answer:256

Step-by-step explanation:

use identity (a+b)^2=a^2+b^2+2ab

then,

(2x+3y)^2=4x^2+9y^2+12xy

so 4x^2+9y^2=136 ----(1) and xy=10 ----(2)

as given  in question  then

(4x^2+9y^2)+12(xy)=136+12x10    -----------------substituting value of(1) and (2)

                                =256