If5cosA=3, find the value of 3tanA-1/6tanA+7
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Answer:
5cosA = 3
cosA = 3/5 = base / hypotenuse
By using Pythagoras theorem
( H )² = ( P )² + ( B )²
( 5 )² = P² + ( 3 )²
25 = P² + 9
25 - 9 = P²
16 = P²
P = √16 = √4×4
P = 4
finding the value
3tanA - 1 / 6TanA+7
3×4/3 - 1 / 6×4/3 +7
cut the multiplication values
=4 - 1 / 2×4 + 7
=3 / 8 + 7
=3 / 15
= 5
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