Math, asked by deepak14397, 11 months ago

if8^x+1=64,what is the value of 3^2x+1​

Answers

Answered by Anonymous
177

Solution:

The given Equation is 8^x+1 = 64

Solve Equation:

8^x+1 = 64

8^x+1 = 8²

x+1 =2

x = 2 - 1

x = 1

To Find :

3^2x +1

Substitute the value of x :

☞3^2(1)+ 1

☞3^2+1

☞3^3

☞27

Answer : 27

Answered by prerna93
52

Answer:

if 8^(x+1)=64

8^(x+1))=8^2

x+1=2

x=2-1

x=1

therefore ,3^2x+1

lets consider value of x

3^2(1)+1

3^2+1

3^3

27.it is the correct answer.

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