Question

ifa=11(242)121,b=14(392)196 then,find c=13(?)169

Answer 1

HELLO.....FRIEND!!

THE ANSWER IS HERE,


=> a=11 (242)121

=> b=14 (392)196

=>c=13 (x)169.

The numbers are in a pattern as

$= > \: x(2 {x}^{2} ) {x}^{2}$

For a, x=11

$= > \: 11(2 ({11)}^{2} ) {11}^{2}$

=> 11 (242)121

For b, x=14

we get,

14 (392)196.

For c, x=13

$= > \: 13(2 ({13})^{2} ) {13}^{2}$

=> 13 (338)169.

So, 338 will come in place of question mark (?).

:-)Hope it helps u.

Answer 2

he friends your answer is

2×169 = 338

hope it will help you..