Question

ifA=15
evaluate: 4cos 2A.sin4A. tan4A-1
​

Answer 1

Answer:

3√3-1

Step-by-step explanation:

Given, A=15

2A=30  4A=60

rewriting the equation, we get,

4cos30.sin60.tan60-1

= (4×√3/2)×√3/2×√3-1

= 4×3/4×√3-1

= 3√3-1

Hope it helps...

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Answer 2

Step-by-step explanation:

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