Math, asked by yashk2134, 8 months ago

IfA=

[

2 a -3

0 2 5

1 1 3

],then find the value of a for which A

-1 exists.​

Answers

Answered by yeswanth2003
1

Answer:

a= -9/5

Step-by-step explanation:

A = [2 a -3

0 2 5

1 1 3]

A. = 2(6-5) -a(0-5) -3(0-2)

= 2 +5a +6

A = 5a +8

given that A = -1

5a +8 = -1

a= -9/5

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