Ifa^2+b^2+c^2=29ab+bc+ca=26,then find the value of a+b+c
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Answer:
9
Given:
a²+b²+c²=29
ab+bc+ac=26
Using Identity:
(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
(a+b+c)²=29+2(26)
(a+b+c)²=29+52=81
(a+b+c)=√81=9.
Hence, (a+b+c)=9.
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