Question

ifa=-2, b=-3 andc=5, then find the value of:
-2a-3b+5c+a²+b²-c²​

Answer 1

Answer:

correct answer is 26

Step-by-step explanation:

• -2(-2)-3(-3)+5(5)+4+9-25
• 4+9+25+4+9-25
• 26

Answer 2

Answer:

we have to substitute in the above equation

=-2a-3b+5c+A2+b2-c2

=-2(-2)-3(-3)+5(5)+(-2^2)+(-3^2)-(5^2)

=4+9+25+4+9-25(here +25 and -25 will get cancelled and the value is '0')

=13+13=26