Question

ifA=(-3,2) and B=(-2,3) then A-B=?

Answer 1

Trigonometric interpretation:

The two points given are A = (- 3, 2) and B = (- 2, 3).

The required distance between A and B is given by A - B.

Now, A - B

= $\sqrt{\{(-3)-(-2)\}^{2}+(2-3)^{2}}$ units

= $\sqrt{(-3+2)^{2}+(2-3)^{2}}$ units

= $\sqrt{(-1)^{2}+(-1)^{2}}$ units

= $\sqrt{1+1}$ units

= $\bold{\sqrt{2}}$ units

$\boxed{A-B=\sqrt{2}}$

Vector interpretation:

Two vectors are $\vec{A}=(-3,2)$ and $\vec{B}=(-2,3)$

So, $\vec{A}-\vec{B}$

= (- 3, 2) - (- 2, 3)

= (- 3 + 2, 2 - 3)

= (- 1, - 1)

$\boxed{A-B=(-1,-1)}$

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