Question

Ifa=3,b=2 find the value of (i) dº + ba (ii) d'+bb (iii) (a+b)(iv) (a−b)"​

Answer 1

Answer:

lf a=3 and b=2

(I) d°+ba

=2°+2(3)

=1+6=7. (two is turned into one

because something

power is 0 then, it will

converted into 1)

(ii)d¹+bb

=2¹+2(2)

=2+4=6

(iii) (a+b)

=(3+2)

=5

(iv)(a-b) ²

=(3-2)² =(3)²+(2)²-2(3+2)

=9+4-2(5)

=13-10

=3

[hope it help you ]