Ifa=5-2√6then find the value of √a-1/√a
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a = 5 - 2root6
a = 2 + 3 - 2. root2 . root3
a = (root3 - root2)^2
roota = root3 - root2
1/roota = 1/(root3 - root2)
= 1/(root3 - root2) * (root3+root2)/(root3+root2)
= (root3 + root2)/ 3 - 2
so, roota - 1/roota = -2root2
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