ifa=6+2√3 find a-1/a
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Heya !!!
A = 6 + 2✓3
1/A = 1/6+2✓3
Rationalizing the denominator 6+2✓3
1/A = 1/6+2✓3 × 6-2✓3/6-2✓3
1/A = (6-2✓3)/( 6+2✓3)(6-2✓3)
1/A = (6-2✓3)/(6)² - (2✓3)²
1/A = (6-2✓3)/36-12
1/A = (6-2✓3)/24
1/A = 2(3-✓3)/24 = 3-✓3/12
Now,
A - 1/A = 6+2✓3 - (3-✓3)/12
=> 12(6+2✓3) - ( 3-✓3)/12
=> 72 + 24✓3 - 3 + ✓3 / 12
=> 69 + 25✓3/12
HOPE IT WILL HELP YOU...... :-)
A = 6 + 2✓3
1/A = 1/6+2✓3
Rationalizing the denominator 6+2✓3
1/A = 1/6+2✓3 × 6-2✓3/6-2✓3
1/A = (6-2✓3)/( 6+2✓3)(6-2✓3)
1/A = (6-2✓3)/(6)² - (2✓3)²
1/A = (6-2✓3)/36-12
1/A = (6-2✓3)/24
1/A = 2(3-✓3)/24 = 3-✓3/12
Now,
A - 1/A = 6+2✓3 - (3-✓3)/12
=> 12(6+2✓3) - ( 3-✓3)/12
=> 72 + 24✓3 - 3 + ✓3 / 12
=> 69 + 25✓3/12
HOPE IT WILL HELP YOU...... :-)
mohdamaan9809:
Thank you
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