IFA ABC-A DEF such that AB = 1.2 cm and DE = 1.4 em, the ratio of the
areas of a ABC and A DEF is
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Given : ABC ~ DEF
AB = 1.2 cm
DE = 1.4 cm
therefore, ratio of areas of ABC and DEF is the ratio of squares of their corresponding sides
ar(ABC) / ar(DEF) = (AB/DE)^2
ar(ABC) / ar(DEF) = (1.2)^2 /(1.4)^2
==> ar(ABC) / ar(DEF) = 36/49
ar(ABC) : ar(DEF) = 36:49
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