Question

.Ifa and ß are the roots of the equation
ax2+bx+c=0 then the roots of the equation
a(2x+1)2-b(2x+1)(3-x)+c(3-x)2=0 are​

Answer 1

Step-by-step explanation:

a(2x+1)2-b(2x+1)(3-x)+c(3-x)2=0

(2bx^2) + (4a -6b + b - 2c)x + = 0

then

let's this equation solution is p and q

then

p + q = -(4a -6b + b - 2c)÷2b

p×q = (2a - 3b +6c )÷2b

given --

a + ß = -b÷a

a×ß = c÷a