Question

IfA and B are two vectors that A=2and B=7 and A×B=3i+2j+6k find the angle between them​

Answer 1

Answer:

30 degrees

Explanation:

|AxB|=|A||B|sin (theta)

sq.root(3^2+2^2+6^2)=2*7*sin(theta)

7=2*7*sin(theta)

sin(theta)=1/2

theta=sin^-1(1/2)

theta=30 deg in anticlockwise direction

Answer 2

Answer:

30 degreee

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