Question

Ifa, ß are the roots of a quadratic equation ax + bx+c 0 (ax0 ), and
a+B aß, then the value of 1 by alpha + 1 by beeta=
​

Answer 1

Answer:

-b/c

Step-by-step explanation:

In quadratic equations:

Sum of roots = -(middle term/first term)

Product of roots = constant term/first term

So, if alpha and beta are zeroes:

Sum of roots = - b/c

Product of roots = c/a

So,

= > 1/alpha + 1/beta

= > (beta + alpha)/alpha.beta

= > (sum of roots)/product of roots

= > (-b/a)/(c/a)

= > -b/c

Answer 2

Step-by-step explanation:

I need the quadratic equation which has the roots of 1/alpha and 1/beeta