ifa+b=2,ab=3 then a^3+b^3=
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Answer:
we know that
a³+b³ = (a+b)³-3ab(a+b)
then put the value of a+b=2 and ab=3
a³+b³=2³-3×3(2)
then a^3+b^3 =8-18
=-10
then the required a³+b³ = -10
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