ifA+B=45 provethat (1+tanA)(1+tanB)=2
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A+B = 45
=> tan(A+B) = tan 45 = 1
=> tanA + tan B = 1 - tanA.tanB
=> tanA + tanB + tanA.tanB = 1
Adding 1 on both sides
=> 1 + tanA + tanB + tanA.tanB = 2
=> (1+tanA).(1+tanB) = 2
=> tan(A+B) = tan 45 = 1
=> tanA + tan B = 1 - tanA.tanB
=> tanA + tanB + tanA.tanB = 1
Adding 1 on both sides
=> 1 + tanA + tanB + tanA.tanB = 2
=> (1+tanA).(1+tanB) = 2
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