IfA→.B→=∣∣∣A→ × B→∣∣∣A→.B→=|A→ × B→| , the angle betweenA→A→ andB→B→ is
Answers
Answered by
1
Explanation:
∣
∣
∣
∣
a
+
b
∣
∣
∣
∣
=
∣
∣
∣
∣
a
−
b
∣
∣
∣
∣
⇒
∣
∣
∣
∣
a
+
b
∣
∣
∣
∣
2
=
∣
∣
∣
∣
a
−
b
∣
∣
∣
∣
2
⇒
∣
∣
∣
∣
a
∣
∣
∣
∣
2
+
∣
∣
∣
∣
b
∣
∣
∣
∣
2
+2
a
.
b
=
∣
∣
∣
∣
a
∣
∣
∣
∣
2
+
∣
∣
∣
∣
b
∣
∣
∣
∣
2
−2
a
.
b
⇒
a
.
b
=0
∴
a
⊥
b
∴θ=90
∘
Similar questions