Question

Ifa, B are the roots of x2 + px + 12 = 0 and a- B = 1, then: value of p ​

Answer 1

Sum of roots = a + b = -p.

Product of roots = ab = 12.

(a - b)² = (a + b)² - 4(ab) = p² - 48 = 1. ==> p = ±7.

Case 1: x² + 7x² + 12 = (x+4)(x+3)=0. x = -4 or -3.

Case 2: x² - 7x + 12 = (x -4)(x-3)=0. x = 4 or 3