Math, asked by bangpink007, 1 month ago

Ifa, B are the zeroes of f(x)=2x² + 8x-8, then prove that a+B-aß=0.

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Answers

Answered by Merci93
5

\sf\underline{Question:}

If α and β are the zeroes of f(x)=2x² + 8x-8, then prove that α+β-αβ =0.

\sf\underline{Answer:}

f(x)=2x² + 8x-8

Here : a = 2 ; b = 8 ; c = -8

Alpha+ Beta is the sum of zeroes

 \alpha  +  \beta  =  \frac{ - b}{a}

 \alpha  +  \beta  =  \frac{ - 8}{2}  =  - 4

Alpha × Beta is the product of the zeroes

 \alpha  \beta  =  \frac{c}{a}

 \alpha  \beta  =  \frac{ - 8}{2}  =  - 4

 \alpha  +  \beta   - \alpha  \beta  =  - 4 - ( - 4)=0

Therefore,

 \alpha   + \beta   - \alpha  \beta  = 0

Have a good evening!

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