Question

Ifa+b+c=0, then evaluate (a+b)(b+c)(c+a)

Answer 1

Answer:

a³+b³+c³ = 3abc

Step-by-step explanation:

Hey mate!

Here is yr answer......

Given,

a+b+c = 0

as we know,

a³+b³+c³ - 3abc = (a+b+c)(a²+b²+c² -ab-bc-ac)

a³ + b³ + c³ -3abc = (0)(a²+b²+c²-ab-bc-ac)

a³+b³+c³ -3abc = 0

a³+b³+c³ = 3abc

Hope it helps....

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