IfA= (x:x is a natural number}; B = {x:x is an
sa natural number}; B = {x: x is an even number}; C = {xx is an
odd natural number}; D = {x:x is a prime number
ber}; D = {x:x is a prime number} then find (i) An B (ii) BUC
(iii) An D (iv) An C. What do you observe ?
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Answered by
1
Answer:
Step-by-step explanation:
i) A∩B = even no ,
Ii) B∪C = natural no,
iii) A∩D = prime no,
iv) A ∩ C = odd natural no,
for union it is natura no , as it consists all the no,
for intersection it is the concern no, in 2nd category
Answered by
0
Answer:
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Explanation:
A={x:xis a natural number}={1,2,3,4,5.....}
B={x:x is an even natural number}={2,4,6,8.....}
C={x:x is an odd natural number}={1,3,5,7,9.......}
D={x:xis a prime number}={2,3,5,7....}
(i) A∩B={x:x is a even natural number}=B
(ii) A∩C={x:x is an odd natural number}=C
(iii) A∩D={x:x is a prime number}=D
(iv) B∩C=ϕ
(v) B∩D={2}
(vi) C∩D={x:xis odd prime number}
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