Question

ifA={x:x²-5x+6=0},b={x:x²-x-2=0} then find A ∪B​

Answer 1

Answer:

{-1,2,3}

Step-by-step explanation:

$\\\tt x^{2} -5x + 6 = 0\\ x^{2} - 3x -2x+ 6 = 0 \\x(x-3) -2(x-3)=0 \\(x-3)(x-2) = 0$

Since x= 2 and 3 satisfies this equation,

A={2,3}

Similarly,

$\\\tt x^{2} -x-2=0\\= x^{2} -2x+x-2=0\\=x(x-2) + (x-2)=0\\=(x-2)(x+1)=0$

Therefore x = -1 and 2 satisfies the equation.

Therefore B={-1,2}

AUB ={-1,2,3}