ifA=x²yz³ and B=xy²z² then find the LCM of A and B ?
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Given that a = x²y³= x ×x ×x × y × y B = xy³ = x × y × y × y
HCF of a and b would be = ( x³,y²,xy³) = x × y × y
HCF = xy²
HCF the product of the smallest power of each common prime factor involved in the numbers.
LCM = x³ y³
LCM is the lowest common factor of each power.
HCF × LCM
xy² × x³y³
AB = x⁴ y⁵
Thus :- AB = HCF × LCM
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