Question

ifA=x²yz³ and B=xy²z² then find the LCM of A and B ?​

Answer 1

Given that a = x²y³= x ×x ×x × y × y B = xy³ = x × y × y × y

HCF of a and b would be = ( x³,y²,xy³) = x × y × y

HCF = xy²

HCF the product of the smallest power of each common prime factor involved in the numbers.

LCM = x³ y³

LCM is the lowest common factor of each power.

HCF × LCM

xy² × x³y³

AB = x⁴ y⁵

Thus :- AB = HCF × LCM

Answer 2

Answer:

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