IfABB x 999= ABC123 (where A, B, C are digits) find the values of A, B, C.
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Answer:
A, B, C = 8,7,6 respectively
Step-by-step explanation:
bcoz,
we know that, the last digit of the number ABC123 is 3.So as the multiply of only 9 and 7 can give the result in last digit 3.
According to this, B = 7
so now the question is,, A77×999 = A7C123
put A = 1,2,.......,9
we find the number A = 8 , in which the result becomes 876123
so A = 8
B = 7
C = 6 .....ans.
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Hey mate ....ur answer is in the attachment
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