Question

Ifalphq and beta are the zeroes of quadratic polynomial x^2-(k+6)x+2(2k-1).find the value of k, if alpha+beta=1/2alpha baeta

Answer 1

Here's your answer..
Please mark as brainliest..

Answer 2

→ Answer : 7

In a quadric polynomial,

→ Sum of zeros = - Coefficient of x/Coefficient of x²

⇒ α + β = - [-(k + 6)]/1

⇒ α + β = k + 6

→ Product of zeros = Constant Term/Coefficient of x²

⇒ αβ = 2(2k - 1)/1

⇒ αβ = 2(2k - 1)

As per the question,

⇒ α + β = αβ/2

⇒ k + 6 = 2(2k - 1)/2

⇒ k + 6 = 2k - 1

⇒ 6 + 1 = 2k - k

⇒ 7 = k or k = 7