Iff areas of two sim triangles are equal,then prove that they are congruent.
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Answered by
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Answer:
Step-by-step explanation:
Use the theorem that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides , then prove that they are congruent.
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Solution:
[Fig is in the attachment]
Given: ΔABC ~ ΔPQR. &
ar ΔABC =ar ΔPQR
To Prove: ΔABC ≅ ΔPQR
Proof: Since, ΔABC ~ ΔPQR
ar ΔABC =ar ΔPQR. (given)
ΔABC / ar ΔPQR = 1
⇒ AB²/PQ² = BC²/QR² = CA²/PR² = 1
[ USING THEOREM OF AREA OF SIMILAR TRIANGLES]
⇒ AB= PQ , BC= QR & CA= PR
Thus, ΔABC ≅ ΔPQR
[BY SSS criterion of congruence]
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Hope this will help you.
Answered by
4
[HeY Mate]
Answer:
Question:
If the areas of two similar triangles are equal, prove that they are congruent.
Solution:
Let ΔABC and ΔPQR be the two similar triangles with equal area.
To Prove: ΔABC ≅ ΔPQR.
Proof:
ΔABC ~ ΔPQR
∴ Area of (ΔABC)/Area of (ΔPQR) = BC2/QR2
⇒ BC2/QR2 =1 [Since, ar (ΔABC) = ar (ΔPQR)]
⇒ BC2/QR2
⇒ BC = QR
Similarly, we can prove that
AB = PQ and AC = PR
Therefore, ΔABC ≅ ΔPQR [SSS criterion of congruence]
I Hope It Helps You✌️
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