Question

ifif 120 gram of propane is burnt in excess of oxygen how many gram of water are produced ​

Answer 1

Explanation:

just see the attachment u have to apply unitary approach to solve these type of questions...

Answer 2

194 g of water is produced if 120 gram of propane is burnt in excess of oxygen

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{120g}{44g/mol}=2.7moles$

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

According to stoichiometry:

1 mole of propane produces = 4 moles of water

2.7 moles of propane produce= $\frac{4}{1}\times 2.7=10.8$ moles of water

Mass of water=$moles\times {\text {molar mass}}=10.8mol\times 18g/mol=194g$

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