Math, asked by adarshboss0358, 9 months ago

Ifk-1,k+1 and 2k+3 are in AP, then the value of k is​

Answers

Answered by sanjukta6741
0

Answer:

k=0

Step-by-step explanation:

The explanation is attached for reference.

If the answer is correct then plzz mark me the brainliest.

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Answered by harshkumarverma481
2

Answer:

k=0

Step-by-step explanation:

(k-1),(k+1),(2k+3),........

2(k+1)=(k-1)+(2k+3) [a,b,c,.....

=>b-a=c-b=>2b=a+c]

2k+2=k-1+2k+3

2k+2=3k+2

2-2=3k-2k

0=k

k=0

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