Ifk-1,k+1 and 2k+3 are in AP, then the value of k is
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0
Answer:
k=0
Step-by-step explanation:
The explanation is attached for reference.
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2
Answer:
k=0
Step-by-step explanation:
(k-1),(k+1),(2k+3),........
2(k+1)=(k-1)+(2k+3) [a,b,c,.....
=>b-a=c-b=>2b=a+c]
2k+2=k-1+2k+3
2k+2=3k+2
2-2=3k-2k
0=k
k=0
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