Question

Ifn2 is even than n is
(a) also odd
(b) also prime
(c) also even
(d) none of these​

Answer 1

Answer:

it is also prime number

Answer 2

Answer:

${ \huge{ \underline{ { \red{ \sf{✯Solution✯}}}}}}$

If n² is even then n is also even.

$\underline{ \sf{ \underline{Let's \: check \: our \: Answer}}}$

Here we taking n² as even. Because in question they mentioned that n² is only even.

➟ Let us take n² as 4. So, (2)² = 4 .

Here n = 2 (even number)

➟ Let us take n² as 16. So, (4)² = 16 .

Here n = 4 (even number)

➟ Let us take n² as 36. So, (6)² = 36 .

Here n = 6 (even number)

We can conclude that if n² is even then n also be as even.

$\therefore { \sf{ \underline{ \pink{ {Option \: C \: is \: your \: Answer}}}}}$