Question

IFor what value of k,(-4) is a zero of the polynomial x²-x-(2k+2)?

Answer 1

Answer:

Zero of the polynomial is -4

p(x)=x²-x-(2k+2)

p(x)=x²-x-2k-2

p(-4)=0

0=-4²-(-4)-2k-2

0=16+4-2k-2

0=18-2k

2k=18

k=18/2=9

k=9

hence, your answer is 9..

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