Question

IFP (0,4) is the mid point of the line segment joining the points Al
b respectively are :
(-2,3) and B(a,b), then values ofa and b respectively are
(a) 2,-3
(b) 2,5
(c)-2,5
(d) 3, -2​

Answer 1

Answer:

Option B is correct

Step-by-step explanation:

We know that mid-point formula is

$x = \frac{x_1 + x_2}{2} \\ \\ y = \frac{y_1 + y_2}{2}$

Here A(-2,3) B(a,b)

mid-point is P(0,4)

so

$0 = \frac{ - 2 + a}{2} \\ \\ a = 2 \\ \\ 4 = \frac{3 + b}{2} \\ \\ 8 = 3 + b \\ \\ b = 8 - 3 \\ \\ b = 5$

Point B(2,5),Option B is correct.

Hope it helps you.

Answer 2

The value of "a and b are b) (2, 5)".

Step-by-step explanation:

Here, $A(x_{1} =-2,y_{1} =3)$ and $B(x_{2} =a,y_{2} =b)$

The mid point of P = (0, 4)

To find, the values of a and b = ?

We know that,

The mid point formula,

$x=\dfrac{x_{1}+x_{2}}{2}, y=\dfrac{y_{1}+y_{2}}{2}$

∴ $\dfrac{-2 +a}{2}=0$

⇒ $-2 +a=0$

⇒ a = 2

Also,

$\dfrac{3+b}{2}=4$

⇒$3+b=4\times 2=8$

⇒ $b=8-3=5$

∴ b = 5

Hence, the value of "a and b are b) (2, 5)".