Question

Ifp= 2, q=1 and r= 3, find the value of i) p2+q2 + r2 ii) 2p2 - q2 + 3r2 iii) p-q-r iv) p3+q3+r3+3pqr v) 3p2q+ 5pq2+ 2pqr vi) p4 + q4- r4​

Answer 1

Answer:

Substituting p=−2,q=−1 and r=3 in the given expression, we get

2p

2

−q

2

+3r

2

=2(−2)

2

−(−1)

2

+3(3)

2

=2(−2×−2)–(−1×−1)+3(3×3)

=2(4)–(1)+3(9)

=8–1+27

=7+27

=34

∴2p

2

−q

2

+3r

2

=34

Answer 2

Answer:

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Step-by-step explanation:

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