Question

IFP(A)=1/2, P(B)=3/4 and Play B)=11/12, then P(4B)is​

Answer 1

Answer:

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Step-by-step explanation:

P(A)= 1/3 

P(B)= 1/4 

Now, P(AUB) = 11/12 

=> P(A)+ P(B) - P(A∩B) = 11/12 

=> P(A∩B) = ( 1/3 + 3/4 ) - 11/12 = 2/12 = 1/6 

Therefore, 

P(B/A)= P(A∩B) / P(A)

          = (1/6) / (1/3) 

          = 1/2

Answer 2

Step-by-step explanation:

p (A)=1/3

P(B)=1/4

Now= p(AUB)=11/12

=(A)+P(B)-P(AUB)=11/12

=P(AUB)=(1/3+3/4)=-11/12=1/6

therefore = P(B/A=P(AUB/P)A 11/12